Message-ID: <1693378109.8687.1664487040635.JavaMail.confluence@dragonknight> Subject: Exported From Confluence MIME-Version: 1.0 Content-Type: multipart/related; boundary="----=_Part_8686_473102128.1664487040634" ------=_Part_8686_473102128.1664487040634 Content-Type: text/html; charset=UTF-8 Content-Transfer-Encoding: quoted-printable Content-Location: file:///C:/exported.html Production calculations

# Production calculations

### Calculations

#### Production

The Potential P50 depends on the Monthl= y Distribution.

With Monthly Distributions the energy production distribution over diffe= rent months can be specified. The production over all months is 100%. By de= fault each month has a production percentage of 8.33% =3D 100% / 12 months.= The input can be either in percentage or in absolute values.

The Potential PN depends on the Confide= nce.

The Production amount gets affected by Standard Deviation and p-Value. W= ith the help of these two values, you can calculate the Safety Reduction be= tween the Reference Scenario (PN) and the P50 Scenario.

Safety Reduction =3D 1 - (Production PN /= Production P50)

The Production PN depends on the Losses= of the Production Units.

### Loss Mode

With losses production diminishing factors can be considered. The losses= are multiplicative linked.

If cable- and transformer losses reduce the production by 2% and grid lo= sses by further 3%, the Production Units have a efficiency of 95.06% =3D 10= 0% x ((1 - 2%) x (1 - 3%)).

### Efficiency Mode

The efficiency sets the efficiency of= the Production Units in percent.

When a facility has a guaranteed avai= lability of 97% the Production Unit has a efficiency of 97% =3D 100% x 97%<= /span>

Degradation is an "age discount", which defines the percentage the Produ= ction Unit decreases with increasing lifetime. Degradation is a dynamic ame= ndment over time series. It's set in percentage per year, but the decrease = occurs every month.

A facility with a yearly Degradation of 1.5% and a Production of 100 MWh= /a respective 8.33 MWh in the first month has the following Production and = Efficiency:

01.2016 02.2016 03.2016 04.2016 05.2016 06.2016 ... 01.2020
Production in MWh per Month 8.33 8.32 8.31 8.30 8.29 8.28 ... 7.84
Efficiency 100% 99.88 99.75 99.63 99.50 99.38   94.17%

The particular Efficiency is calculated as follows:

Efficiency(t) =3D Efficiency x (1 - month= ly Degradation)t
Efficiency(06.2016) =3D 100% x (1 - (1.5%/12= ))5 =3D 99.38%

The displayed Efficiency for each Production Units and for the total par= k shows the average Efficiency over the whole Project Lifetime.

### Loss Interaction

All loss modes are multiplicative linked. The Efficiency of a facility w= ith an availability of 97%, cable= - and transformer losses of 2% and a Degradation of 1.5% is calculated as f= ollows:

Efficiency(t) =3D 100% x (1 - Losses= i) x Efficiency x (1 - Degradation)

The Efficiency after 15 months (Start =3D 0) is 93.64%:

Efficiency(15) =3D 100% x (1 - 2%) x 97% = x (1 - 1.5% / 12)15 =3D  93.29%

The Production amount depends on the Pr= oduction Units.

The Production amount depends on the Potential P50, on the Security Cut = resulting from the selected p-Value and from the Standard Deviation, on Los= ses (Loss, Efficiency and Degradation) and on the Monthly Distribution.

The electricity production is calculated according to the following form= ula:

Production PN(t) =3D Potential P50 x (1 -= Security Cut) x Efficiency(t) x Monthly Distribution(t) x Active(t)

with Active(t) =3D 1 if t >=3D Start a= nd t < End; otherwise Active(t) =3D 0

### Key Data

Calculation Unit
Full-load Hou= rs Full-load Hou= rs =3D Production amount per year / Power h/a
Potential PN<= /span> Potential PN = =3D Potential P50 x (1 - Confidence) MWh/a
Production PN= Production PN= =3D Potential PN x Efficiency MWh/a
Efficiency

Efficiency= =3D 100% x (1 - Lossesi) x Efficiency x (1-Degradation)t

For the Loss mode "Deg= radation" the average value over the Project Lifetime is shown.

<= /td>
%

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